Iterative solution to the Fibonacci sequence in COBOL

I've decided to learn cobol by contributing to Rosetta Code, a site that aims to show each as many different programming language's solution to a given problem.

Below is the iterative solution to the fibonacci sequence, which takes in input from the user's standard input keyboard.

View on Rosetta Code

Program-ID. Fibonacci-Sequence.
Data Division.
Working-Storage Section.
  01  FIBONACCI-PROCESSING.
    05  FIBONACCI-NUMBER  PIC 9(36)   VALUE 0.
    05  FIB-ONE           PIC 9(36)   VALUE 0.
    05  FIB-TWO           PIC 9(36)   VALUE 1.
  01  DESIRED-COUNT       PIC 9(4).
  01  FORMATTING.
    05  INTERM-RESULT     PIC Z(35)9.
    05  FORMATTED-RESULT  PIC X(36).
    05  FORMATTED-SPACE   PIC x(35).
Procedure Division.
  000-START-PROGRAM.
    Display "What place of the Fibonacci Sequence would you like (<173)? " with no advancing.
    Accept DESIRED-COUNT.
    If DESIRED-COUNT is less than 1
      Stop run.
    If DESIRED-COUNT is less than 2
      Move FIBONACCI-NUMBER to INTERM-RESULT
      Move INTERM-RESULT to FORMATTED-RESULT
      Unstring FORMATTED-RESULT delimited by all spaces into FORMATTED-SPACE,FORMATTED-RESULT
      Display FORMATTED-RESULT
      Stop run.
    Subtract 1 from DESIRED-COUNT.
    Move FIBONACCI-NUMBER to INTERM-RESULT.
    Move INTERM-RESULT to FORMATTED-RESULT.
    Unstring FORMATTED-RESULT delimited by all spaces into FORMATTED-SPACE,FORMATTED-RESULT.
    Display FORMATTED-RESULT.
    Perform 100-COMPUTE-FIBONACCI until DESIRED-COUNT = zero.
    Stop run.
  100-COMPUTE-FIBONACCI.
    Compute FIBONACCI-NUMBER = FIB-ONE + FIB-TWO.
    Move FIB-TWO to FIB-ONE.
    Move FIBONACCI-NUMBER to FIB-TWO.
    Subtract 1 from DESIRED-COUNT.
    Move FIBONACCI-NUMBER to INTERM-RESULT.
    Move INTERM-RESULT to FORMATTED-RESULT.
    Unstring FORMATTED-RESULT delimited by all spaces into FORMATTED-SPACE,FORMATTED-RESULT.
    Display FORMATTED-RESULT.